[Solution by Dr. Abubacker] The vapour pressure curve of the solution lies below that of the pure liquid solvent. The solid (frozen) solvent curve meets the solution curve at the new freezing point $T_f$, which is lower than $T_f^\circ$ (where the frozen solvent curve meets the pure liquid solvent curve). Option (1) shows this arrangement, with $\Delta T_f=T_f^\circ-T_f$. Answer (1).