Consider the following reaction occurring in the blast furnace: $ ext{Fe}_3 ext{O}_{4(s)}+4 ext{CO}_{(g)} o3 ext{Fe}_{(l)}+4 ext{CO}_{2(g)}$. 'x' kg of iron is produced when $2.32 imes10^3$ kg $ ext{Fe}_3 ext{O}_4$ and $2.8 imes10^2$ kg CO are brought together in the furnace. The value of 'x' is ______. (nearest integer) Given: molar mass of $ ext{Fe}_3 ext{O}_4=232\ ext{g mol}^{-1}$, molar mass of $ ext{CO}=28\ ext{g mol}^{-1}$, molar mass of $ ext{Fe}=56\ ext{g mol}^{-1}$

Question

Consider the following reaction occurring in the blast furnace: $	ext{Fe}_3	ext{O}_{4(s)}+4	ext{CO}_{(g)}	o3	ext{Fe}_{(l)}+4	ext{CO}_{2(g)}$. 'x' kg of iron is produced when $2.32	imes10^3$ kg $	ext{Fe}_3	ext{O}_4$ and $2.8	imes10^2$ kg CO are brought together in the furnace. The value of 'x' is ______. (nearest integer) Given: molar mass of $	ext{Fe}_3	ext{O}_4=232\ 	ext{g mol}^{-1}$, molar mass of $	ext{CO}=28\ 	ext{g mol}^{-1}$, molar mass of $	ext{Fe}=56\ 	ext{g mol}^{-1}$

Dr. Abubacker · Accepted Answer

[Solution by Dr. Abubacker] $	ext{Fe}_3	ext{O}_4=\frac{2.32	imes10^6}{232}=10^4$ mol; $	ext{CO}=\frac{2.8	imes10^5}{28}=10^4$ mol. CO is the limiting reagent (needs $4$ mol per mol $	ext{Fe}_3	ext{O}_4$). Fe formed $=\frac34	imes10^4=7500$ mol $=7500	imes56$ g $=420$ kg. Answer: 420.

Explanation

Reviewed by Dr. Abubacker

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