This is a numerical-answer question. The correct answer is shown below.
[Solution by Dr. Abubacker] $\text{Cu}^{2+}$ gives a chocolate-brown precipitate ($\text{Cu}_2[\text{Fe(CN)}_6]$), $\text{Fe}^{3+}$ gives Prussian blue, and $\text{Zn}^{2+}$ gives a white/bluish-white precipitate ($\text{Zn}_2[\text{Fe(CN)}_6]$). The others do not give a characteristic precipitate in their standard identification tests. Count $=3$. (Medium confidence: answer follows the official key.) Answer: 3.