The equation of the chord, of the ellipse $\frac{x^2}{25}+\frac{y^2}{16}=1$, whose mid-point is $(3,1)$ is :

Question

Dr. Abubacker · Accepted Answer

[Solution by Dr. Abubacker] Chord with mid-point $(x_1,y_1)$: $T=S_1$, i.e. $\frac{3x}{25}+\frac y{16}=\frac9{25}+\frac1{16}$. Multiplying by $400$: $48x+25y=144+25=169$. Answer (1).

Q. The equation of the chord, of the ellipse $\frac{x^2}{25}+\frac{y^2}{16}=1$, whose mid-point is $(3,1)$ is :

Explanation

Reviewed by Dr. Abubacker

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