[Solution by Dr. Abubacker] There are $2^4=16$ matrices. $|A|=a_{11}a_{22}-a_{12}a_{21}\ne0$ requires exactly one of the products to be $1$: $a_{11}a_{22}=1$ and $a_{12}a_{21}=0$ ($3$ ways), or the reverse ($3$ ways). So $6$ matrices are invertible and $P(E)=\frac6{16}=\frac38$. Answer (3).