The increase in pressure required to decrease the volume of a water sample by $0.2\%$ is $P imes10^5\ ext{Nm}^{-2}$. Bulk modulus of water is $2.15 imes10^9\ ext{Nm}^{-2}$. The value of P is ......

Question

The increase in pressure required to decrease the volume of a water sample by $0.2\%$ is $P	imes10^5\ 	ext{Nm}^{-2}$. Bulk modulus of water is $2.15	imes10^9\ 	ext{Nm}^{-2}$. The value of P is ......

Dr. Abubacker · Accepted Answer

[Solution by Dr. Abubacker] $\Delta P=B\frac{\Delta V}V=2.15	imes10^9	imes0.002=4.3	imes10^6\ 	ext{N/m}^2=43	imes10^5$. So $P=43$. Answer: 43.

Q. The increase in pressure required to decrease the volume of a water sample by $0.2\%$ is $P\times10^5\ \text{Nm}^{-2}$. Bulk modulus of water is $2.15\times10^9\ \text{Nm}^{-2}$. The value of P is ......

Explanation

Reviewed by Dr. Abubacker

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