Q. Match List - I with List - II. [table] List I (Transition metal ion) | List II (Spin only magnetic moment, B.M.) ; (A) $Ti^{3+}$ | (I) 3.87 ; (B) $V^{2+}$ | (II) 0.00 ; (C) $Ni^{2+}$ | (III) 1.73 ; (D) $Sc^{3+}$ | (IV) 2.84 [/table] Choose the correct answer from the options given below :

A) (A) -(III), (B) - (I), (C) - (IV), (D) - (II)
B) (A) -(III), (B) - (I), (C) - (II), (D) - (IV)
C) (A) -(IV), (B) - (II), (C) - (III), (D) - (I)
D) (A) - (II), (B) - (IV), (C) - (I), (D) - (III)
Explanation

[Solution by Dr. Abubacker] $\mu=\sqrt{n(n+2)}$: $Ti^{3+}$ ($d^1$, $n=1$) $=1.73$; $V^{2+}$ ($d^3$, $n=3$) $=3.87$; $Ni^{2+}$ ($d^8$, $n=2$) $=2.84$; $Sc^{3+}$ ($d^0$) $=0$. So A-III, B-I, C-IV, D-II. Answer (1).

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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