In Carius method of estimation of halogen, $0.25$ g of an organic compound gave $0.15$ g of silver bromide $(AgBr)$. The percentage of Bromine in the organic compound is ...... $ imes10^{-1}\%$ (Nearest integer). (Given : Molar mass of Ag is $108$ and Br is $80\ g\ mol^{-1}$)

Question

In Carius method of estimation of halogen, $0.25$ g of an organic compound gave $0.15$ g of silver bromide $(AgBr)$. The percentage of Bromine in the organic compound is ...... $	imes10^{-1}\%$ (Nearest integer). (Given : Molar mass of Ag is $108$ and Br is $80\ g\ mol^{-1}$)

Dr. Abubacker · Accepted Answer

[Solution by Dr. Abubacker] Mass of Br $=\frac{80}{188}	imes0.15=0.0638$ g. Percentage $=\frac{0.0638}{0.25}	imes100=25.5\%=255	imes10^{-1}\%$. Answer: 255.

Q. In Carius method of estimation of halogen, $0.25$ g of an organic compound gave $0.15$ g of silver bromide $(AgBr)$. The percentage of Bromine in the organic compound is ...... $\times10^{-1}\%$ (Nearest integer). (Given : Molar mass of Ag is $108$ and Br is $80\ g\ mol^{-1}$)

Explanation

Reviewed by Dr. Abubacker

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