This is a numerical-answer question. The correct answer is shown below.
[Solution by Dr. Abubacker] $i=\frac{\text{normal M}}{\text{observed M}}=\frac{164}{65.6}=2.5$. $MX_2\rightleftharpoons M^{2+}+2X^-$ gives $i=1+2\alpha\Rightarrow\alpha=0.75=75\%$. Answer: 75.