$v = \sqrt{\frac{T}{m}} = \left\lbrack \frac{m^{'}g}{\frac{M}{t}} \right\rbrack^{1/2} = \left\lbrack \frac{m'lg}{M} \right\rbrack^{1/2}$ It follows from here, $\frac{\mathrm{\Delta}v}{v} = \frac{1}{2}\left\lbrack \frac{\mathrm{\Delta}m'}{m} + \frac{\mathrm{\Delta}l}{l} + \frac{\mathrm{\Delta}M}{M} \right\rbrack$ $= \frac{1}{2}\left\lbrack \frac{0.1}{3.0} + \frac{0.001}{1.000} + \frac{0.1}{2.5} \right\rbrack$ $= \frac{1}{2}\lbrack 0.03 + 0.001 + 0.04\rbrack$ $= 0.036$ Percentage error in the measurement=3.6