Q. If force $(F)$, length $(L)$ and time $(T)$ are assumed to be fundamental units, then the dimensional formula of the mass will be
A) $FL^{- 1}T^{2}$
B) $FL^{- 1}T^{- 2}$
C) $FL^{- 1}T^{- 1}$
D) $FL^{2}T^{2}$
Explanation
Let$\ m = KF^{a}L^{b}T^{c}$ Substituting the dimension of $\lbrack F\rbrack = \left\lbrack MLT^{- 2} \right\rbrack,\ \lbrack C\rbrack = \lbrack L\rbrack$ and $\lbrack T\rbrack = \lbrack T\rbrack$ And comparing both sides, we get $m = FL^{- 1}T^{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.