Q. The magnetic force on a point moving charge is $\overrightarrow{F} = q(\overrightarrow{V} \times \overrightarrow{B})$. Here, $q =$electric charge $\overrightarrow{V} =$ velocity of the point charge $\overrightarrow{B} =$magnetic field The dimensions of $\overrightarrow{B}$
A) $\lbrack MLT^{- 1}A\rbrack$
B) $\lbrack MLT^{- 2}A^{- 1}\rbrack$
C) $\lbrack MT^{- 1}A^{- 1}\rbrack$
D) None of these
Explanation
Force $\overrightarrow{F} = q\overrightarrow{v} \times \overrightarrow{B}$ Or $F = qvB$ sin $\theta$ $\therefore\ \ \ \ \ \lbrack B\rbrack = \left\lbrack \frac{F}{qv} \right\rbrack = \frac{\lbrack MLT^{- 2}\rbrack}{\lbrack ATLT^{- 1}\rbrack} = \lbrack MT^{- 2}A^{- 1}\rbrack$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.