Q. Electric displacement is given by $D = \varepsilon E$, Here, $\varepsilon =$electric permittivity $E =$electric field strength The dimensions of electric displacement are
A) $\lbrack ML^{- 2}TA\rbrack$
B) $\lbrack L^{- 2}T^{- 1}A\rbrack$
C) $\lbrack L^{- 2}TA\rbrack$
D) None of these
Explanation
Electric displacement, $D = \varepsilon E$ Unit of $D = \frac{C^{2}}{Nm^{2}}\frac{N}{C}$ $\therefore\ \ \ \ \ \ \ \lbrack D\rbrack = \left( \frac{C}{m^{2}} \right) = \frac{\lbrack AT\rbrack}{\lbrack L^{2}\rbrack} = \lbrack L^{- 2}TA\rbrack$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.