Q. The dimension of $\frac{1}{2}\epsilon_{0}E^{2}$, where $\epsilon_{0}$ is permittivity of free space and $E$ is electric field, is
A) $MLT^{1}$
B) $ML^{2}T^{- 2}$
C) $ML^{- 1}T^{- 2}$
D) $ML^{2}T^{- 1}$
Explanation
$\left\lbrack \frac{1}{2} \in_{0}E^{2} \right\rbrack =$ [Energy density] $= \frac{ML^{2}T^{- 2}}{L^{3}} = ML^{- 1}T^{- 2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.