Q. The surface tension is $T = \frac{F}{l},$ then the dimensions of surface tension are
A) $\lbrack MLT^{- 2}\rbrack$
B) $\lbrack MT^{- 2}\rbrack$
C) $\lbrack M^{0}L^{0}T^{0}\rbrack$
D) None of these
Explanation
Surface tension, $T = \frac{F}{l}$ $\therefore\ \ \ \lbrack T\rbrack = \frac{\lbrack F\rbrack}{\lbrack l\rbrack}$ $= \frac{\left\lbrack MLT^{- 2} \right\rbrack}{\lbrack L\rbrack} = \left\lbrack ML^{0}T^{- 2} \right\rbrack = \left\lbrack MT^{- 2} \right\rbrack$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.