Q. $X = 3YZ^{2}$ find dimension of $\ Y$ in $(MKSA)$ system, If $X$ and $Z$ are the dimensions of capacity and magnetic field respectively
A) $M^{- 3}L^{- 2}T^{- 4}A^{- 1}$
B) $ML^{- 2}$
C) $M^{- 3}L^{- 2}T^{4}A^{4}$
D) $M^{- 3}L^{- 2}T^{8}A^{4}$
Explanation
$Y = \frac{X}{3Z^{2}} = \frac{M^{- 1}L^{- 2}T^{4}A^{2}}{\left\lbrack MT^{- 2}A^{- 1} \right\rbrack^{2}} = \lbrack M^{- 3}L^{- 2}T^{8}A^{4}\rbrack$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.