Volume $V = I^{3} = \left( 1.2 \times 10^{- 2}m \right)^{3} = 1.728 \times 10^{- 6}m^{3}$ $\because\$length $l$has two significance figures. Therefore, the correct answer is $V = 1.7 \times 10^{- 6}m^{3}$
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