Q. If 1 g cm $s^{- 1}$= $x$ newton-second, then the number $x$ is equal to
A) $1 \times 10^{- 3}$
B) $3.6 \times 10^{- 3}$
C) 1$\times 10^{- 5}$
D) 6$\times 10^{- 4}$
Explanation
$x = \frac{1gcms^{- 1}}{T^{2}} = \frac{1gcms^{- 1}}{1kg \times 1ms^{- 1} \times 1s}$ $= \frac{1gcms^{- 1}}{10^{3}g \times 10^{2}cms^{2} \times 1s} = 10^{- 5}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.