Volume $V = l \times b \times t$ $= 12 \times 6 \times 2.45 = 176.4\ cm^{3}$ $V = 1.764 \times 10^{2}\ cm^{3}$ Since, the minimum number of significant figure is one in breadth, hence volume will also contain only one significant figure. Hence, $V = 2 \times 10^{2}\ cm^{3}$