Q. The power of lens is $P = \frac{1}{f},\$where $f$ is focal length of the lens . The dimensions of power of lens are
A) $\lbrack LT^{- 2}\rbrack$
B) $\lbrack M^{0}L^{- 1}T^{0}\rbrack$
C) $\lbrack M^{0}L^{0}T^{0}\rbrack$
D) None of these
Explanation
Power of lens $P = \frac{1}{f}$ $\therefore\ \ \lbrack P\rbrack = \frac{1}{\lbrack f\rbrack} = \frac{1}{\lbrack L\rbrack} = \lbrack M^{0}L^{- 1}T^{0}\rbrack$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.