Q. If $S = \frac{1}{3}ft^{3},f$ has the dimensions of
A) $\lbrack M^{0}L^{- 1}T^{3}\rbrack$
B) $\lbrack MLT^{- 3}\rbrack$
C) $\lbrack M^{0}L^{1}T^{- 3}\rbrack$
D) $\lbrack M^{0}L^{- 1}T^{- 3}\rbrack$
Explanation
Here, $\lbrack f\rbrack = \frac{\lbrack S\rbrack}{\left\lbrack t^{3} \right\rbrack} = \lbrack M^{0}LT^{- 3}\rbrack$.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.