Q. The dimensional formula for Planck’s constant $(h)$ is
A) $ML^{- 2}T^{- 3}$
B) $ML^{2}T^{- 2}$
C) $ML^{2}T^{- 1}$
D) $ML^{- 2}T^{- 2}$
Explanation
$E = hv \Rightarrow \left\lbrack ML^{2}T^{- 2} \right\rbrack = \lbrack h\rbrack\lbrack T^{- 1}\rbrack \Rightarrow \lbrack h\rbrack = \lbrack ML^{2}T^{- 1}\rbrack$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.