Q. A pressure of $10^{6}$ dyne $cm^{- 2}$ is equivalent to
A) $10^{5}N\ m^{- 2}$
B) $10^{4}\ N\ m^{- 2}$
C) $10^{6}N\ m^{- 2}$
D) $10^{7}N\ m^{- 2}$
Explanation
1 Newton = $10^{5}$ dyne and 1m=100 cm
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.