Q. If force $(F),\$length $(L)$ and time $(T)$ are assumed to be the fundamental units, then the dimensional formula of the mass will be
A) $\left\lbrack {FL}^{- 1}T^{2} \right\rbrack\$
B) $\left\lbrack {FL}^{- 1}T^{- 2} \right\rbrack$
C) $\left\lbrack {FL}^{- 1}T^{- 1} \right\rbrack$
D) $\left\lbrack {FL}^{2}T^{- 2} \right\rbrack$
Explanation
From Newton’s second law $\ \ \ \ \ \ Force\ (F) = Mass\ (M) \times acceleration$ Dimensions of $\lbrack F\rbrack = \left\lbrack MLT^{- 2} \right\rbrack$ $\therefore\ \ \ \ \ \ \ \ \ \ \ \ \lbrack M\rbrack = \left\lbrack FL^{- 1}T^{2} \right\rbrack$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.