The specific resistance $\rho$ of a circular wire of radius $r$. Resistance $R$ and and length $l$ is given by $\rho = \frac{\pi r^{2}R}{l}.$ Given, $r = 0:(24 \pm 0.02)$cm, $R = (30 \pm 1)\Omega$ and $l = (4.80 \pm 0.01)$cm. The percentage error in $\rho$ is nearly

Question

Dr. Abubacker · Accepted Answer

Required percentage $= \frac{2 	imes 0.02}{0.24} 	imes 100 + \frac{1}{30} 	imes 100 + \frac{0.01}{4.80} 	imes 100$ $= 16.7 + 3.3 + 0.2$ $= 20\%$

Q. The specific resistance $\rho$ of a circular wire of radius $r$. Resistance $R$ and and length $l$ is given by $\rho = \frac{\pi r^{2}R}{l}.$ Given, $r = 0:(24 \pm 0.02)$cm, $R = (30 \pm 1)\Omega$ and $l = (4.80 \pm 0.01)$cm. The percentage error in $\rho$ is nearly

Explanation

Reviewed by Dr. Abubacker

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