Q.
The circular scale of a screw gauge has 50 divisions and pitch of 0.5 mm. Find the diameter of sphere. Main scale reading is 2.
A) 1.2
B) 1.25
C) 2.20
D) 2.25
Explanation
Least count LC $= \frac{Pitch}{Number\ of\ divisions\ on\ circular\ scale}$ $= \frac{0.5}{50} = 0.01\ mm$ Now, diameter of ball $= (2 \times 0.5\ mm) + (25 - 5)(0.01) = 1.2mm$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.