Q. The dimensions of universal gravitational constant are
A) $M^{- 2}L^{2}T^{- 2}$
B) $M^{- 1}L^{3}T^{- 2}$
C) ${ML}^{- 1}T^{- 2}$
D) $ML^{2}T^{- 2}$
Explanation
$F = \frac{Gm_{1}m_{2}}{d^{2}} \Rightarrow G = \frac{Fd^{2}}{m_{1}m_{2}}$ $\therefore\lbrack G\rbrack = \frac{\left\lbrack MLT^{- 2} \right\rbrack\lbrack L^{2}\rbrack}{\lbrack M^{2}\rbrack} = {\lbrack M}^{- 1}L^{3}T^{- 2}\rbrack$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.