Explanation

$Average\ value\ = \frac{\ 2.63 + 2.56 + 2.42 + 2.71 + 2.80}{5}$ $= 2.62\ sec$ Now $\left| \mathrm{\Delta}T_{1} \right| = 2.63 - 2.62 = 0.01$ $\left| \mathrm{\Delta}T_{2} \right| = 2.62 - 2.56 = 0.06$ $\left| \mathrm{\Delta}T_{3} \right| = 2.62 - 2.42 = 0.20$ $\left| \mathrm{\Delta}T_{4} \right| = 2.71 - 2.62 = 0.09$ $\left| \mathrm{\Delta}T_{5} \right| = \ 2.80 - 2.62 = 0.18$ Mean absolute error $\mathrm{\Delta}T = \frac{\left| \mathrm{\Delta}T_{1} \right| + \left| \mathrm{\Delta}T_{2} \right| + \left| \mathrm{\Delta}T_{3} \right| + \left| \mathrm{\Delta}T_{4} \right| + \left| \mathrm{\Delta}T_{5} \right|}{5}$ $= \frac{0.54}{5} = 0.108 = 0.11\ sec$