Q. Given, potential difference $V$=$(8 \pm 0.5)$ volt and current $I = (2 \pm 0.2)$A. The value of resistance $R$ is
A) $4 \pm 16.25\%$
B) $4 \pm 6.25\%$
C) $4 \pm 10\%$
D) $4 \pm 8\%$
Explanation
$V = (8 + 0.5)$ $I = (2 + 0.2)$ $R = \frac{8}{2} = 4$ $\frac{\mathrm{\Delta}R}{R}\% = \left( \frac{\mathrm{\Delta}V}{V} + \frac{\mathrm{\Delta}I}{I} \right)$ $= \left( \frac{0.5}{8} + \frac{0.2}{2} \right) \times 100 = 16.25\%$ $\therefore\ \ R = (4 \pm 16.25\%)$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.