Given, $v = at + bt^{2}$ Applying the law of homogeneity $\lbrack v\rbrack = \left\lbrack bt^{2} \right\rbrack$ Or $\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \left\lbrack LT^{- 1} \right\rbrack = \left\lbrack bT^{2} \right\rbrack$ Or $\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \lbrack b\rbrack = \left\lbrack LT^{- 3} \right\rbrack$