Q. Find the dimensions of electric permittivity

A) $\left\lbrack A^{2}M^{- 1}L^{- 3}T^{4} \right\rbrack$
B) $\left\lbrack A^{2}M^{- 1}L^{- 3}T^{0} \right\rbrack$
C) $\left\lbrack {AM}^{- 1}L^{- 3}T^{4} \right\rbrack$
D) $\left\lbrack A^{2}M^{0}L^{- 3}T^{4} \right\rbrack$
Explanation

From Coulomb’s law, the force of attraction/repulsion between two point charges $q\ and\ q$ separated by distance $r$ is $\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ F = \frac{1}{4\pi\varepsilon_{0}}\frac{q^{2}}{r^{2}}$ $\Rightarrow \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \varepsilon_{0} = \frac{1}{4\pi}\ .\frac{q^{2}}{Fr^{2}}$ Where $\varepsilon_{0}$ is electric permittivity. Dimensions of $\varepsilon_{0} = \frac{\lbrack AT\rbrack^{2}}{\left\lbrack MLT^{- 2} \right\rbrack\left\lbrack L^{2} \right\rbrack\ }$ $\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \left\lbrack \varepsilon_{0} \right\rbrack = \left\lbrack A^{2}M^{- 1}L^{- 3}T^{- 4} \right\rbrack$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.