Position of body with acceleration ‘$a$’ is given by $x = Ka^{m}t^{n}$, here $t$ is time. Find dimensions of $\ m$ and $n$

Question

Dr. Abubacker · Accepted Answer

As $x = ka^{m} 	imes t^{n}$ $\left\lbrack M^{0}LT^{0} ightbrack = \left\lbrack LT^{- 2} ightbrack^{m}\lbrack Tbrack^{n} = \lbrack L^{m}T^{- 2m + n}brack$ $	herefore m = 1$ and $- 2m + n = 0\ \Rightarrow n = 2$

Q. Position of body with acceleration ‘$a$’ is given by $x = Ka^{m}t^{n}$, here $t$ is time. Find dimensions of $\ m$ and $n$

Explanation

Reviewed by Dr. Abubacker

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