Magnetic field $B = \frac{F}{qv\sin\theta}$ Hence, $1\ T = \frac{1N}{1C\ \times 1\ {ms}^{- 1}}$ $\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = \frac{1\ N}{1\ As\ \times 1\ {ms}^{- 1}}\ \ \ \ (\because 1C = 1\ ampere\ \times 1\ second)$ $\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = 1\ {NA}^{- 1}m^{- 1}$