Q. Coefficient of thermal conductivity has the dimensions
A) [$MLT^{- 3}K^{- 1}$]
B) [$ML^{3}T^{3}K^{2}$]
C) [$ML^{3}T^{- 3}K^{- 2}$]
D) [$M^{2}L^{3}T^{- 3}K^{2}$]
Explanation
Heat $Q = \frac{KA(\theta_{1} - \theta_{2})t}{d}$ or $K = \frac{Qd}{A(\theta_{1} - \theta_{2})t}$ $\lbrack k\rbrack = \frac{\left\lbrack ML^{2}T^{- 2} \right\rbrack\lbrack L\rbrack}{\lbrack L\rbrack^{2}\lbrack K\rbrack\lbrack T\rbrack} = \lbrack MLK^{- 1}T^{- 3}\rbrack$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.