Q. Which of the following is the unit of specific heat?
A) $Jkg\ {^\circ}C^{- 1}$
B) ${Jkg}^{- 1}\ {^\circ}C^{- 1}$
C) $kg\ {^\circ}{CJ}^{- 1}$
D) $J/{kg}^{- 1}\ {^\circ}C^{- 2}$
Explanation
We know that Specific heat $= \frac{Q}{m\ \mathrm{\Delta}t}$ $Unit\ of\ specific\ heat\ = \frac{unit\ of\ heat}{unit\ of\ mass\ \times \ unit\ of\ temperature}$ $\therefore Unit\ of\ specific\ heat = \frac{J}{kg{^\circ}C} = {Jkg}^{- 1}{^\circ}C^{- 1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.