Q. A student has measured the length of a wire equal to 0.04580 m. This value of length has the number of significant figures equal to

A) Five
B) Four
C) Six
D) None of these
Explanation

We will use the general rule of addition by making the powers same. $ie,$ we will add $3.8 \times 10^{- 6}$ and $42 \times 10^{- 6}$ we get $\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = 45.8 \times 10^{- 6} = 4.58 \times 10^{- 5}$ As least number of significant figures in given values are 2, so We round off the result to $4.6 \times 10^{- 5}.$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.