Q. If the acceleration due to gravity is 10$\ ms^{- 2}$ and the units of length and time are changed in kilometer and hour respectively, the numerical value ofacceleration is

A) 360000
B) 72000
C) 36000
D) 129600
Explanation

$n_{2} = n_{1}\left\lbrack \frac{L_{1}}{L_{2}} \right\rbrack^{1}\left\lbrack \frac{T_{1}}{T_{2}} \right\rbrack^{- 2} = 10\left\lbrack \frac{m}{km} \right\rbrack^{2}\left\lbrack \frac{\sec}{hr} \right\rbrack^{- 2}$ $n_{2} = 10\left\lbrack \frac{m}{10^{3}m} \right\rbrack^{1}\left\lbrack \frac{\sec}{3600\ sec} \right\rbrack^{- 2}$=129600

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.