Q. If $E =$energy, $G =$ gravitational constant, $I =$ impulse and $M =$ mass, the dimensions of $\frac{GIM^{2}}{E^{2}}$ are same as that of
A) Time
B) Mass
C) Length
D) Force
Explanation
$E = \left\lbrack ML^{2}T^{- 2} \right\rbrack,\ G = \left\lbrack M^{- 1}L^{3}T^{- 2} \right\rbrack,\ I = \lbrack MLT^{- 1}\rbrack$ $\therefore\frac{GIM^{2}}{E^{2}} = \frac{\left\lbrack M^{- 1}L^{3}T^{- 2} \right\rbrack\left\lbrack MLT^{- 1} \right\rbrack\lbrack M^{2}\rbrack}{\left\lbrack ML^{2}T^{- 2} \right\rbrack^{2}} = \lbrack T\rbrack$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.