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Class XII Chapter 2 – Inverse Trigonometric Functions Maths
Question 1:
Find the principal value of Answer
Let sin-1 Then sin y =
We know that the range of the principal value branch of sin−1 is and sin
Therefore, the principal value of
We know that the range of the principal value branch of cos−1 is
.
Therefore, the principal value of .
Find the principal value of cosec−1 (2) Answer
Let cosec−1 (2) = y. Then,
We know that the range of the principal value branch of cosec−1 is
Therefore, the principal value of
We know that the range of the principal value branch of tan−1 is
Therefore, the principal value of
We know that the range of the principal value branch of cos−1 is
Therefore, the principal value of
Find the principal value of tan−1 (−1) Answer
Let tan−1 (−1) = y. Then,
We know that the range of the principal value branch of tan−1 is
Therefore, the principal value of
We know that the range of the principal value branch of sec−1 is
Therefore, the principal value of
We know that the range of the principal value branch of cot−1 is (0,π) and
Therefore, the principal value of
We know that the range of the principal value branch of cos−1 is [0,π] and
.
Therefore, the principal value of
We know that the range of the principal value branch of cosec−1 is
Therefore, the principal value of
Find the value of Answer
Find the value of if sin−1 x = y, then
(C) (D)
Answer
It is given that sin−1 x = y.
We know that the range of the principal value branch of sin−1 is Therefore, .
Find the value of is equal to
(A) π (B) (C) (D) Answer
Question 1:
Prove Answer
To prove:
Let x = sinθ. Then, We have,
R.H.S. =
= 3θ
= L.H.S.
Prove Answer
To prove:
Let x = cosθ. Then, cos−1 x =θ. We have,
Prove Answer
To prove:
Prove Answer
To prove:
Write the function in the simplest form:
Answer
Write the function in the simplest form:
Answer
Put x = cosec θ ⇒ θ = cosec−1 x
Write the function in the simplest form:
Answer
Write the function in the simplest form:
Answer
Write the function in the simplest form:
Answer
Write the function in the simplest form:
Answer
Find the value of Answer
Let . Then,
Find the value of Answer
Let x = tan θ. Then, θ = tan−1 x.
Let y = tan Φ. Then, Φ = tan−1 y.
On squaring both sides, we get:
Hence, the value of x is
If , then find the value of x.
Answer
Hence, the value of x is
We know that sin−1 (sin x) = x if , which is the principal value branch of sin−1x.
Here,
Now, can be written as:
We know that tan−1 (tan x) = x if , which is the principal value branch of tan−1x.
Here,
Now, can be written as:
Find the values of Answer
Let . Then,
Find the values of is equal to
Answer
We know that cos−1 (cos x) = x if , which is the principal value branch of cos
−1x.
Here,
Now, can be written as:
The correct answer is B.
Find the values of is equal to
Answer
Let . Then,
We know that the range of the principal value branch of .
∴
The correct answer is D.
Question 1:
Find the value of Answer
We know that cos−1 (cos x) = x if , which is the principal value branch of cos
−1x.
Here,
Now, can be written as:
Find the value of Answer
We know that tan−1 (tan x) = x if , which is the principal value branch of tan −1x.
Here,
Now, can be written as:
Now, we have:
Now, we have:
Prove Answer
Now, we will prove that:
Now, we have:
Using (1) and (2), we have
Prove Answer
Prove [Hint: putx = cos 2θ]
Answer
Prove Answer
Solve Answer
Solve is equal to
(A) (B) (C) (D) Answer
Let tan−1 x = y. Then,
The correct answer is D.
Solve , then x is equal to
(A) (B) (C) 0 (D)
Answer
Therefore, from equation (1), we have
Put x = sin y. Then, we have:
But, when , it can be observed that:
is not the solution of the given equation.
Thus, x = 0.
Hence, the correct answer is C.
Solve is equal to
Answer
Hence, the correct answer is C.